Disproof of a conjecture of Jacobsthal

نویسندگان
چکیده

برای دانلود رایگان متن کامل این مقاله و بیش از 32 میلیون مقاله دیگر ابتدا ثبت نام کنید

اگر عضو سایت هستید لطفا وارد حساب کاربری خود شوید

منابع مشابه

Disproof of a conjecture of Jacobsthal

For any integer n ≥ 1, let j(n) denote the Jacobsthal function, and ω(n) the number of distinct prime divisors of n. In 1962 Jacobsthal conjectured that for any integer r ≥ 1, the maximal value of j(n) when n varies over N with ω(n) = r is attained when n is the product of the first r primes. We show that this is true for r ≤ 23 and fails at r = 24, thus disproving Jacobsthal’s conjecture.

متن کامل

Disproof of the Mertens Conjecture

The Mertens conjecture states that  M(x)  < x ⁄2 for all x > 1, where M(x) = n ≤ x Σ μ(n) , and μ(n) is the Mo bius function. This conjecture has attracted a substantial amount of interest in its almost 100 years of existence because its truth was known to imply the truth of the Riemann hypothesis. This paper disproves the Mertens conjecture by showing that x → ∞ lim sup M(x) x − ⁄2 > 1. 06 ....

متن کامل

Disproof of a Conjecture of Neumann-Lara

We disprove the following conjecture due to Vı́ctor Neumann-Lara: for every pair (r, s) of integers such that r > s > 2, there is an infinite set of circulant tournaments T such that the dichromatic number and the cyclic triangle free disconnection of T are equal to r and s, respectively. Let Fr,s denote the set of circulant tournaments T with dc(T ) = r and − →ω 3 (T ) = s. We show that for eve...

متن کامل

Disproof of a Conjecture on Univalent Functions

We disprove the Gruenberg-RRnning-Ruscheweyh conjecture, namely that Re d g z (z) > 0; jzj < 1; holds for g 2 S, the set of normalized univalent functions in the unit disk D , and d analytic with jd 0 (z)j Re d(z) in D , d(0) = 1. Here stands for the Hadamard product.

متن کامل

Disproof of an admissibility conjecture of Weiss

Two conjectures on admissible control operators by George Weiss are disproved in this paper. One conjecture says that an operator B defined on an infinite-dimensional Hilbert space U is an admissible control operator if for every element u ∈ U the vector Bu defines an admissible control operator. The other conjecture says that B is an admissible control operator if a certain resolvent condition...

متن کامل

ذخیره در منابع من


  با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید

ژورنال

عنوان ژورنال: Mathematics of Computation

سال: 2012

ISSN: 0025-5718,1088-6842

DOI: 10.1090/s0025-5718-2012-02581-6